For the hydrolysis of methyl acetate in aqueous solution, the following results were obtained :
(a) Show that it follows pseudo first order reaction, as the concentration of water remains constant.
(b) Calculate the average rate of reaction between the time interval 10 to 20 seconds.
(Given: log 2 = 0.3010, log 4 = 0.6021).
OR
(a) For a reaction A + B → P, the rate is given by Rate = k[A][B]2
(i) How is the rate of reaction affected if the concentration of B is doubled ?
(ii) What is the overall order of reaction if A is present in large excess ?
(b) A first order reaction takes 30 minutes for 50% completion. Calculate the time required for 90% completion of this reaction.
(a) [A]0 = 0.01 Mol/L
[A] = 0.05 Mol/L at time t = 10s.

k = 0.0693 s-1
t = 20 s

K = 0.0693 s-1, Thus its pseudo first order reaction.
(b) The average rate constant is


= 0.0025 mol L-1s-1
OR
(a) (i) Since the given reaction has order 2 with respect to reactant B, if the concentration of B is doubled in the given reaction, then the rate of reaction will become four times.
(ii) It the concentration of B is doubled i.e., [B]2 the overall reaction will be two, because if A is present in large excess, then the reaction will be independent of the concentration of A and will be dependent only on the concentration of B.
Order of reaction = 2.
(b) t1/2= 30 min
[R] = [R]0 – 90% of [R]0





t = 99.7 min.
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