An aromatic compound ‘A’ of molecular formula C7H6O2 undergoes a series of reactions as shown below. Write the structures of A, B, C, D and E in the following reactions :

OR
(a) Write the structure of main products when benzene diazonium chloride reacts with the following reagents :
(i) H3PO2 + H2O
(ii) CuCN/KCN
(iii) H2O
(b) Arrange the following in the increasing order of their basic character in an aqueous solution:
C2H5NH2, (C2H5)2NH, (C2H5)3N
(c) Give a simple chemical test to distinguish between the following pair of compounds:
C6H5 – NH2 and C6H5 – NH – CH3
A : C6H5COOH (Benzoic acid)

B : C6H5NH2 (Aniline)

(because amide reacts with bromine water to form Aniline)
C : C6H5NHCOCH3 (N-phenyl ethanamide)

(because aniline reacts with acitic anhydride it produces N-phenyl ethanamide)
D : C6H5CH2NH2 (Benzylamine)

(When benzyl amide reacts with LiAlH4, then through reduction process carbonyl compounds changes into produces Benzyl Amine).
E: C6H4(Br)3 (NH2) (2, 4, 6 – Tribromoaniline)
When Aniline reacts with Bromine water(Br2 aq.) then through the substitution process, it produces 2, 4, 6 – Tribromoaniline.

OR
(a)
(i)

When benzene diazonium chloride reacts with mild reducing agents such as hypophosphorous acid, it undergoes a nitrogen displacement reaction. Here, the benzene diazonium chloride is reduced to benzene. H3PO2 itself is oxidized to phosphorous acid. Nitrogen formed escapes as gas.
(ii)

Benzene diazonium chloride on reaction with CuCN/KCN, undergoes nitrogen displacement reaction. The presence of Cu(I) ion helps the introduction of the nucleophilic CN- ion. The product formed is Benzonitrile, with the escape of nitrogen as gas. The reaction is known as Sandmeyer reaction.
(iii)

The hydrolysis of benzene diazonium chloride gives Phenol as a product with the evolution of nitrogen gas. When the diazonium salt solution is heated and the temperature is allowed to rise to 283°K, the nucleophile OH- is introduced, forming phenol.
(b) C2H5NH2 < (C2H5)3N < (C2H5)2NH
+I effect of three C2H5 groups increases the enormous availability of lone pair of electrons on the nitrogen atom than +I effect of 2 ethyl groups. Thus the order of basicity is I < III < II.
(c) C6H5—NH2 (Primary amine) and C6H5—NH—CH3 (Secondary amine) can be distinguished by Hinsberg’s test. In this test amines are treated with Hinsberg reagent, benzenesulphonyl chloride (C6H5SO2Cl). Primary amines reacts with this reagent to form N-alkylbenzene sulphonyl amide which is soluble in alkali but secondary amines gives sulphonamide which is insoluble in alkali.
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