Q11 of 50 Page 1

In Figure 1, common tangents AB and CD to the two circles with centres O1 and O2 intersect at E. Prove that AB = CD.


From the given figure,


AE = CE and BE = ED [Since tangents drawn from an external point are equal]


On adding, we get


⇒ AE + BE = CE + ED


⇒ AB = CD


Hence proved.


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