Q31 of 50 Page 1

Solve for x:

; x ≠ 5, 7


Given equation





Cross-multiplying,


⇒ 3 (2x2 – 22x + 58) = 10 (x2 – 12x + 35)


⇒ 6x2 – 66x + 174 = 10x2 – 120x + 350


⇒ 4x2 – 54x + 176 = 0


⇒ 2x2 – 27x + 88 = 0


⇒ 2x2 – 16x – 11x + 88 = 0


⇒ 2x (x – 8) – 11 (x – 8) = 0


⇒ (x – 8) (2x – 11) = 0


⇒ x = 8 and x = 11/2


∴ The solutions of x are 8 and 11/2.


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