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All India - 2014
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Q24 of 50 Page 1

Prove that the diagonals of a rectangle ABCD, with vertices A (2, -1), B (5, -1), C (5, 6) and D (2, 6) are equal and bisect each other.

Given vertices of rectangle ABCD are A (2, -1), B (5, -1), C (5, 6) and D (2, 6).


Diagonal AC


= √58 units


Diagonal BD


= √58 units


∴ Diagonals are equal.


Mid-point of AC


Mid-point of BD


∴ Diagonals also bisect each other.


Hence proved.


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