Prove that the diagonals of a rectangle ABCD, with vertices A (2, -1), B (5, -1), C (5, 6) and D (2, 6) are equal and bisect each other.
Given vertices of rectangle ABCD are A (2, -1), B (5, -1), C (5, 6) and D (2, 6).
Diagonal AC ![]()
= √58 units
Diagonal BD ![]()
= √58 units
∴ Diagonals are equal.
Mid-point of AC ![]()
Mid-point of BD ![]()
∴ Diagonals also bisect each other.
Hence proved.
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