A container open at the top, is in form of a frustum of a cone of height 24 cm with radii of its lower and upper circular ends as 8 cm and 20 cm respectively. Find the cost of the milk which can completely fill the container at the rate of ₹21 per litre. [Use π = 22/7]
Given height, h = 24 cm
Upper radius, R = 20 m
Lower radius, r = 8 cm
We know that volume of a frustum of a cone = 1/3 πh (R2 + r2 + Rr)
⇒ Volume of the container ![]()
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We know that 1000cm3 = 1 L
⇒ Volume ![]()
Rate per litre = ₹21
⇒ Cost of the milk in the container ![]()
= 329.472
∴ Cost of the milk = ₹329. 47
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