A 20 μF capacitor is joined to a battery of emf 6.0 V through a resistance of 100 Ω. Find the charge on the capacitor 2.0 ms after the connections are made.
Concepts/Formulas used:
Charging a capacitor:
A capacitor of capacitance C is being charged using a battery of emf ϵ through a resistance R . A switch S is also connected in series with the capacitor. The switch is initially open. The capacitor is uncharged at first. At t=0, the switch is closed
The charge is at any t>0 is given by:
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Note that
is known as time constant.
Given,
Capacitance, ![]()
EMF of battery, ![]()
Resistance, ![]()
Now,
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Also,
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We know that,
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At t = 2.0ms,
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Hence, the charge on the capacitor at t = 2.0ms is 76μC.
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