In a typical Indian Bugghi (a luxury cart drawn by horses), a wooden plate is fixed on the rear on which one person can sit. A bugghi of mass 200 kg is moving at a speed of 10 km/h. As it overtakes a school boy walking at a speed of 4 km/h, the boy sits on the wooden plate. If the mass of the boy is 25 kg, what will be the new velocity of the bugghi?
Ans. ![]()
Initial momentum of the school boy before sitting = 4×25
= 100 kg km/h
Initial momentum of the bugghi before the boy sat on it
= 10×200 = 2000 kg km/h
Total initial momentum of the bugghi and the school boy
= 2000+100 = 2100 kg km/h
Let the new velocity of the bugghi be v km/h.
Final momentum of the bugghi after the school boy sat on it
= v×(100+25)
= 125v kg km/h
Applying conservation of total linear momentum,
⇒ 125v = 2100
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∴ The new velocity of the bugghi after the process of sitting = 28/3 km/h
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