A cube solid is made up of two elements A and B. The elements of A forms hcp while atoms of element B occupy two-third of the octahedral voids. What is the formula of the solid?
Let the no. of atoms of A forming the hcp be x
So, the no. of octahedral voids = x
And the no. of tetrahedral voids = 2x
As the atoms of element A forms HCP and atoms of B occupies 2/3 of the octahedral voids, so the ratio of atoms of A and B are x:(2/3)x
• A:B=3:2
• The formula of the solid is A3B2
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