Q2 of 111 Page 252

The position, velocity and acceleration of a particle executing simple harmonic motion are found to have magnitudes 2 cm, 1 ms-1 and 10 m s-2 at a certain instant. Find the amplitude and the time period of the motion.

4.9 cm, 0.28 s

Given,


x = 2 cm,


v = 1 m/s = 100 cm/s., and


a = 10 m/s2. = 1000 cm/s2.


Using the Formula,





negative symbol was just to show that the force is opposing in nature.


∴




Now,



∴





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