Q35 of 111 Page 252

A pendulum clock giving correct time at a place where g = 9.800 m s-2 is taken to another place where it loses 24 seconds during 24 hours, Find the value of g at this new place.

9.795 m s-2

When the clock is at g = 9.8 m/s2 T = 2.00 sec


When clock is at g1 it loses 24 seconds in 24 hours


We have T = 2∏ T1 =


l = . g --------->1 = 2.000


This length does not change in the new place T12


l = (T12/4∏2). g1--------->2


From 1 and 2


. g = . g1


g1 = (T2 /T12) . g


=


=


= 9.746 m/s2


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