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12. Simple Harmonic Motion
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Q3 of 111 Page 252

A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal?

5√2 cm

Let’s assume at the distance x from its mean position, kinetic energy is equal to potential energy.


Now,


We have two formulae.




Since, they are equal at a distance x.







At this point, Kinetic and potential energy will be equal.


Now,


On putting the value of amplitude we get,





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1

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The position, velocity and acceleration of a particle executing simple harmonic motion are found to have magnitudes 2 cm, 1 ms-1 and 10 m s-2 at a certain instant. Find the amplitude and the time period of the motion.

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Questions · 111
12. Simple Harmonic Motion
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