Q3 of 100 Page 16

Find the length of a chord which is at a distance of 4 cm from the centre of the circle of radius 6 cm.

Radius of circle (OA) = 6 cm

Distance (OC) = 4 cm


In , by using Pythagoras theorem


AC2 + OC2 = OA2


AC2 + 42 = 62


AC2 = 36 – 16


AC2 = 20


AC = 4.47 cm


We know that,


The perpendicular distance from centre to chord bisects the chord


AC = BC = 4.47 cm


Then,


AB = 4.47 + 4.47


= 8.94 cm


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1

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