Q2 of 100 Page 17

The radius of a circle is 6 cm. The perpendicular distance from the centre of the circle to the chord which is 8 cm in length, is

Let, O be the centre of the circle with chord AB = 8cm

And,


OC be the perpendicular bisector of AC


AO = 6cm


AC = 4cm


In AOC,


OA2 = AC2 + OC2


62 = 42 + OC2


OC2 = 20


OC = 25

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