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16. Circles
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Q17 of 100 Page 17

In Fig. 16.188, ABCD is a cyclic quadrilateral. Find the value of x.

∠FDC + ∠CDA = 180o (Linear pair)

80o + ∠CDA = 180o


∠CDA = 100o


Since, ABCD is a cyclic quadrilateral


∠ADC + ∠ABC = 180o


100o + ∠ABC = 180o


∠ABC = 80o


Now,


∠ABC + ∠ABF = 180o (Linear pair)


80o + x = 180o


x = 180o – 80o


= 100o


More from this chapter

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15

In Fig. 16.187, ∠BAD=78°, ∠DCF=x° and ∠DEF=y°. Find the values of x and y.

16

In a cyclic quadrilateral ABCD, if ∠A-∠C=60°, prove that the smaller of two is 60°.

18

ABCD is a cyclic quadrilateral in which:

(i) BC||AD, ∠ADC=110° and ∠BAC=50°. Find ∠DAC.


(ii) ∠DBC=80° and ∠BAC=40° Find ∠BCD.


(iii) ∠BCD=100° and ∠ABD=70°. Find ∠ADB.

19

Prove that the perpendicular bisectors of the sides of a cyclic quadrilateral are concurrent.

Questions · 100
16. Circles
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