Q6 of 100 Page 17

In Fig. 16.197, AOC is a diameter if the circle and arc AXB=arc BYC. Find ∠BOC.

Given that,

Arc AXB = Arc BYC (i)


Since,


Arc AXBYC is the arc equal to half circumference


And,


Angle subtended by half circumference at centre is 180°


Arc AXBYC = Arc AXB + Arc BYC


Arc AXBYC = Arc BYC + Arc BYC


Arc AXBYC = Arc AXBYC


Now,


∠BOC = ∠AOC


∠BOC = * 180°


∠BOC = 120°


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