Q18 of 100 Page 17

The chord of a circle is equal to its radius. The angle substended by this chord at the minor arc of the circle is

Let AB be the chord of circle equal to radius r

OA = OB = r (Radii)


Therefore,


OA = OB = AB


OBC is equilateral triangle


Each angle = 60°


Hence,


Angle surrounded by AB at minor arc = (Reflex * ∠AOD)


= (360o – 60o)


= 150o

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