Q8 of 47 Page 1

Prove that the points (3, 0), (6, 4) and (- 1, 3) are the vertices of a right angled isosceles triangle.

Let the A(3, 0), B(6, 4) and C(- 1, 3) are three vertices.


Now using distance formula for two points A(x1, y1) and B(x2, y2)



We have




= 5 units






= 5 units


Now, AB > BC = AC


Therefore, if ABC is a right angled triangle. AB should be hypotenuse. BC and AC should be other two sides.(i.e. perpendicular and base)


And should satisfy the Pythagoras theorem, that says


(hypotenuse)2 = (perpendicular)2 + (base)2


AB2 = BC2 + AC2


Taking RHS




= LHS


Hence ABC is a right angled triangle.


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