As observed from the top of a light house, 100 m high above sea level, the angles of depression of a ship, sailing directly towards it, changes from 30° to 60°. Find the distance travelled by the ship during the period of observation. (Use √3 = 1.73)

Let AB be the light house, B be the top of light house,
And C and C' be the positions of ship as angle of depression changes from 30° to 60°
We can draw a mathematical diagram for the above problem.
We know that, ![]()
In ∆ABC
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AC = 173 m
In ∆ABC'
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AC' = 57.8 m (appx)
Distance travelled by ship
AC - AC' = 173 - 57.8 = 115.2 m
Couldn't generate an explanation.
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