The sums of first n terms of three arithmetic progressions are S1, S2 ans S3 respectively. The first term of each A.P. is 1 and their common differences are 1, 2 and 3 respectively. Prove that S1 + S3 = 2S2.
As we know that sum of An AP, upto first n terms is
![]()
Where S = sum of first n terms
a = first term , d = common difference
For first AP a = 1, d = 1
![]()
![]()
For second AP a = 1 , d = 2
![]()
![]()
For second AP a = 1 , d = 3
![]()
![]()
Adding S1 and S3
![]()
![]()
Hence proved.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
