Q25 of 47 Page 1

Solve for x:

Given: 



On taking LCM we get,



On cross multiplying, we get,


 


(2x + 3)(x + 4) = 4(x + 1)(x + 2)


 


(2x2 + 8x + 3x + 12) = 4(x2 + 2x + x + 2)


 


2x2 + 11x + 12 = 4x2 + 12x + 8


 


2x2 + x - 4 = 0


 


As we know for an equation ax2 + bx + x = 0


 


We have


 



 


Here a = 2, b = 1 and c = - 4


 



 


Or


 



 

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