Q21 of 271 Page 315

Integrate the functions.


⇒


⇒


⇒


Now, Let us consider


Let x2 + 2x + 3 = t


⇒ (2x + 2)dx = dt


… (1)


And, now let us consider


⇒ x2 + 2x + 3 = x2 + 2x + 1 + 2 = (x +1)2 + (2


⇒


Using eq. (1) and (2), we get,


⇒


⇒


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