Integrate the rational functions.

Let 
⇒ x = A(x - 1)(x + 2) + B(x + 2) + C( x – 1)2 …(1)
Substituting x = -1 in equation (1), we get,
B = ![]()
Equating the coefficients of x2 and constant term, we get,
A + C = 0
-2A + 2B + C = 0
A =
and c = ![]()
Thus,





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