Integrate the rational functions.


Dividing (x3 + x + 1) by x2 -1, we get,

Let 
Now, 2x + 1 = A(x – 1) + B(x + 1) …(1)
Substituting x = 1 and -1 in equation (1), we get,
A =
and B = ![]()
Thus,


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