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7. Integrals
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Q15 of 271 Page 338

Evaluate

Let I =

Put x2 = t ⇒ 2x dx = dt


When x = 0; t = 0


When x = 1; t = 1


Substituting t and dt in I


⇒ I = = � []


⇒ I =


∴ = � (e – 1)


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Questions · 271
7. Integrals
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