Q20 of 271 Page 322

Integrate the rational functions.

Now,

Multiplying numerator and denominator by x³, we get,

Now, let x⁴ = t

4x³dx = dt

Thus,

Let

1 = A(t – 1) + Bt …(1)

Substituting t = 0 and 1 in (1), we get

A = -1 and B = 1

Integrate the rational functions.

[Hint: Put e^x = t]