Let I = cos 2x = 2cos2x – 1cos2x = putting the value cos2x in I⇒ I = []⇒ I = ⇒ I = = π/4∴ = π/4

Q12 of 271 Page 338

Evaluate

Let I =

cos 2x = 2cos²x – 1

cos²x =

putting the value cos²x in I

⇒ I = []

⇒ I =

⇒ I = = π/4

∴ = π/4

Evaluate