Q2 of 47 Page 1

In Fig. 1, AB is a 6 m high pole and CD is a ladder inclined at an angle of 60 � to the horizontal and reaches up to a point D of pole. If AD = 2.54 m. Find the length of the ladder. [Use √3 = 1.73]

From the given figure, we have

BD = AB – AD


= 6 – 2.54


= 3.46 m


Now, in right triangle DBC we have:





∴ Length of the ladder =



Hence, the length of the ladder is 4 m


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