Q16 of 47 Page 1

Solve for x:

We have,

.


.


4x2 + 10x + 6 = 0


2 (2x2 + 5x + 3) = 0


2x2 + 3x + 2x + 3 = 0


(2x + 3) (x + 1) = 0


x + 3 = 0



Ox + 1 = 0


x = - 1



∴ x = -1 is the only solution


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