If the sum of first 7 terms of an A.P. is 49 and that of its first 17 terms is 289, find the sum of first n terms of the A.P.
Let us assume the 1st term be a and common differed be d
It is given in the question that,
S7 = 49 and =S17 = 289
We know that,
.
∴
.
.
2a + 6d = 14 (i)
Also,
.
+ 16d = 34 (ii)
Now, by solving (i) and (ii) we get:
-0d = - 20
∴ d = 2
tting the value of d in (i), we get:
2a + 12 = 14
= 2
a = 1
∴

.
.
Hence,
Proved
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