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Delhi-2016
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Q18 of 47 Page 1

Solve for x:

We have,





(2x2 + 4) (x – 2) = (2x – 11) (x2 + x – 2)


2x3 + 4x – 4x2 – 8 = 2x3 – 11x2 + 2x2 – 11x – 4x + 22


5x2 + 19x = 30


5x2 + 19x – 30 = 0


5x2 + 25x – 6x – 30 = 0


(x + 5) (5x – 6) = 0



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Questions · 47
Delhi-2016
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