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7. Coordinate Geometry
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Q30 of 77 Page 7


Find a point on the line through A(5, -4) and B(-3, 2), that is, twice as farfrom A as from B.


SOLUTION:

Let the required point be P(x, y).
Then, AP = 2PB
AP: PB = 2: 1
Therefore
 and

Â
So, the required point is

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Questions · 77
7. Coordinate Geometry
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