Q23 of 77 Page 7

Find the equation of the perpendicular bisector of the line segment joining points (7, 1) and (3, 5).

Given: points (7, 1) and (3, 5)


To find: The equation of perpendicular bisector.


Formula Used:


section formula:


If point P (x, y) divides the line segment A(x1,y1) and B(x2,y2)


Then the coordinates of P are:



Explanation:


The points are A (7, 1) and B(3, 5).


Coordinates of midpoint of line AB




Therefore, coordinates of midpoint of AB are (5, 3)


Slope of the line = = 2


Negative reciprocal of slope =


Equation of line y = mx + C






2y = - x + 11


x + 2y = 11


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