p-Dichlorobenzene has higher m.p. than those of o- and m-isomers. Discuss.
p-Dichlorobenzene is more symmetrical than o-and m-isomers. Because it fits more closely and easily in the crystal lattice than o-and m-isomers. Therefore, more energy is required to break the crystal lattice of p-dichlorobenzene. Therefore, p-dichlorobenzene is symmetrical and has a higher melting point and lower solubility than o-and m-isomers due to strong force of attraction in crystal. Therefore more energy required to break lattice and will not easily be soluble.

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