Q10 of 153 Page 7

If x = a sin θ and y = b cos θ, what is the value of b2x2 + a2y2 ?

Given: x = a sin θ and y = b cos θ

⇒ x2 = a2 sin2 θ and y2 = b2 cos2 θ ………(i)


To find: b2x2 + a2y2


Consider b2x2 + a2y2 = b2 a2 sin2 θ + a2 b2 cos2 θ


= a2 b2 (sin2 θ + cos2 θ)


= a2 b2 (1) [∵ sin2 θ + cos2 θ = 1]


= a2 b2


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