(sec A + tan A) (1 − sin A) =
To find: (sec A + tan A) (1 − sin A)
Consider (sec A + tan A) (1 − sin A)
We know that ![]()
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∵ (a + b) (a – b) = a2 – b2
∴ ![]()
Also, sin2 A + cos2 A = 1 ⇒ 1 – sin2 A = cos2 A
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