If
, then find the value of 2 cot2θ + 2.
Given: ![]()
To find: 2 cot2 θ + 2
∵ ![]()
⇒ cosec2 θ = 32 = 9
Also, 1 + cot2 θ = cosec2 θ
⇒ cot2 θ = cosec2 θ – 1 = 9 – 1 = 8
⇒ 2 cot2 θ + 2 = 2 (8) + 2 = 16 + 2 = 18
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