If 5x = sec θ and
, find the value of
.
Given: 5x = sec θ
![]()
………(i)
And ![]()
![]()
![]()
………(ii)
To find: ![]()
Consider
[Using (i)]
[Using (ii)]
![]()
Now, as 1 + tan2 θ = sec2 θ
⇒ 1 = sec2 θ – tan2 θ
![]()
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