Q9 of 153 Page 7

The value of (1 + cot θ − cosec θ) (1 + tan θ + sec θ) is

To find: (1 + cot θ − cosec θ) (1 + tan θ + sec θ)

Consider (1 + cot θ − cosec θ) (1 + tan θ + sec θ)

[∵ (a – b) (a + b) = a² – b²]

[∵ sin² θ + cos² θ = 1]

is equal to

(cosec θ − sin θ) (sec θ − cos θ) (tan θ + cot θ) is equal