The volume of a cube is increasing at the rate of 9 cm3/s. How fast is its surface area increasing when the length of an edge is 10 cm?
Let x be the length of an edge of the cube, V be the volume and S
be the surface area at any time t. Then,
V = x3 and S = 6x2
Also,




Now,
S = 6x2
[using (1)]


Thus, the surface area is increasing at the rate of 3.6 cm2/s.
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