Consider f:
given by
Show that f is bijective. Find the inverse of f and hence find f-1(0) and x such that f-1(x) = 2.
Given function is


To prove f is bijective
one-one
Let x1, x2∈ 
d f(x1) = f(x2)

⇒ 12x1x2 + 9x2 + 16x1 + 12 = 12x1x2 + 9x1 + 16x2 + 12
⇒ 7x1 = 7x2
⇒ x1 = x2
Hence f is one-one.
Onto
Let y ∈ 
Then,
f(x) = y

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Clearly, x ∈ R for all y ∈
. Also, x ≠ (-4/3).
Because, x = (-4/3)

⇒ 12y - 9 = -16 + 12y
⇒ -9 = -16 (which is not possible)
Thus, for each y ∈
there exists 
such that

So, f is onto.
Thus, f is both one-one and onto. Consequently, it is invertible.
Now,
f(f-1(x)) = x for all x ∈ R - [4/3]

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Now,

Also given that-
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⇒ 4x-3 = 8-6x
⇒ 10x = 11
∴ x = 11/10
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