A variable plane which remains at a constant distance 3p from the origin cuts the coordinate axes at A, B, C. Show that the locus of the centroid of triangle ABC is 
Intercept form of plane is


Now distance of plane (1) from (0,0,0) is-



squaring both sides-

Now for the locus of the centroid we must have
x = (a/3), y = (b/3) & z = (c/3)
⇒ a = 3x, b = 3y & c = 3z
∴ equation (2) becomes




Hence Proved.
Couldn't generate an explanation.
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