Determine the product
and use it to solve the system of equations x – y + z = 4, x – 2y – 2z = 9, 2x + y + 3z = 1.



= 8I3
Now,
we have-
x - y + z = 4
x - 2y - 2z = 9
2x + y + 3z = 1
Writing these equations in matrix form-

⇒ AX = B
where,

If |A| ≠ 0
Then the solution of the equations by matrix method is given by-
X = A-1B
Now,
Expanding along C1
|A| = [(1)(-6+2)-(1)(-3-1)+(2)(2+2)] = [(1)(-4)-(1)(-4)+(2)(4)]
= [-4+4+8]
= 8
we know that-
A(adj A) = |A|In = (adj A)A
Comparing this with

we get-

.
Thus,
.
Hence,
x = 3, y = -2, z = -1
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