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Q8 of 45 Page 1

Show that the function f(x) = x3 - 3x2 + 6x - 100 is increasing on R.

We have-

f(x) = x3 - 3x2 + 6x - 100


⇒ f'(x) = 3x2 - 6x + 6


⇒ f'(x) = 3(x2 - 2x + 2)


⇒ f'(x) = 3[(x-1)2 + 1] ≥ 0 for all x ∈ R


So, f(x) is increasing function for all x ∈ R.


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Questions · 45
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