Q2 of 84 Page 48

If p(y) = y2 - 3√2 + 1 then find p(3√2)

Put x = 3√2 throughout the polynomial

⇒ (3√2)2 – (3√2 × 3√2) + 1


⇒ (9 × 2) – (9 × 2) + 1


⇒ 18 – 18 + 1


p(3√2) = 1


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