Find the factors of the polynomials given below.
3y2 – 2y – 1
3y2 – 2y – 1
⟹ 3y2 – 3y + y – 1
⟹ 3y (y - 1) + 1 (y - 1)
⟹ (3y + 1) (y – 1)
Therefore, the factors of the given polynomial = (3y + 1) (y – 1)
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