For each of the following polynomial, find and
p(y) = y2 – 2y + 5
To find: p (1)
Put x = 1 in the given polynomial
p (1) = (1)2 – 2 × 1 + 5
= 1 – 2 + 5
= -1 + 5
= 4
To find: p (0)
Put x = 0 in the given polynomial
p (0) = 0 – 0 + 5
= 5
To find: p (-2)
Put x = -2 in the given polynomial
p (-2) = (-2)2 – 2 × (-2) + 5
= 4 + 4 + 5
p (-2) = 13
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.