Polynomials bx2 + x + 5 and bx3 – 2x + 5 are divided by polynomial x – 3 and the remainders are
and
respectively. If m – n =0 then find the value of b.
Put x = 3 in the first polynomial:
b× (3)2 + 3 + 5 = m
9b + 8 = m ………………………………….. (i)
Put x = 3 in the second polynomial
b× (3)3 -2× 3 + 5 = n
27b -6 + 5 = n
27b -1 = n …………………………………. (ii)
Equation (i) – (ii)
m –n = 9b + 8 – (27b -1)
but m-n = 0
9b + 8 -27b + 1 = 0
-18b + 9 = 0
18b = 9
b = 9/18
b = 1/2
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