Q1 of 26 Page 79

Distance of chord AB from the center of a circle is 8 cm. Length of the chord AB is 12 cm. Find the diameter of the circle.


Given that OP = 8 cm


And AB = 12 cm


We know that a perpendicular drawn from the center of a circle on its chord bisects


the chord.


∴ AP = PB = 6 cm


In the right angled ΔOAP using Pythagoras theorem,


⇒ OA2 = OP2 + AP2


⇒ OA2 = 82 + 62


⇒ OA2 = 64 + 36


⇒ OA2 = 100


⇒ OA = 10cm


So, the diameter of the circle is (2×10) = 20cm (Diameter = 2×Radius).


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