Radius of a circle is 34 cm and the distance of the chord from the center is 30 cm, find the length of the chord.

Given that
Radius = 34cm
So, OA = 34cm
And OP = 30 cm
We know that a perpendicular drawn from the center of a circle on its chord bisects
the chord.
∴ AP = PB,
AB = 2PB
In the right angled ΔOAP using Pythagoras theorem,
⇒ OA2 = OP2 + AP2
⇒ 342 = 302 + AP2
⇒ 1156 = 900 + AP2
⇒ AP2 = 256
⇒ AP = 16cm
So, the length of chord is 16× 2 = 32cm (AB = 2AP)
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